I am trying to calculate a point on one side of a road using a pin found on the other side for direction. I used the % offset command in the form of 1..2%+20.117 expecting a point to be created so that the road would be 20.117m wide..... It didn't work!
Is there a bug reported for this command?
% offset command
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I just tried a couple here and it seems to work for me.
Maybe try it without the + as it is not required to tell it to go to the right, only the  is required to go to the left.
====================================
> COGO
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <5>3
Options: +/ or Pt..Pt+Angle
Enter Quadrant Bearing like QDD.MMSS:<>: 3..4%6
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:50
Enter the Solve Point: <6>6
Enter Description:<>:
3 N09°41'44"W 50.359 99.191 43.329 6
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <6>3
Options: +/ or Pt..Pt+Angle
Enter Quadrant Bearing like QDD.MMSS:<>: 3..4%8
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:50
Enter the Solve Point: <7>
Enter Description:<>:
3 S09°41'44"E 50.636 85.391 45.687 7
====================================
Cheers,
Maybe try it without the + as it is not required to tell it to go to the right, only the  is required to go to the left.
====================================
> COGO
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <5>3
Options: +/ or Pt..Pt+Angle
Enter Quadrant Bearing like QDD.MMSS:<>: 3..4%6
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:50
Enter the Solve Point: <6>6
Enter Description:<>:
3 N09°41'44"W 50.359 99.191 43.329 6
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <6>3
Options: +/ or Pt..Pt+Angle
Enter Quadrant Bearing like QDD.MMSS:<>: 3..4%8
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:50
Enter the Solve Point: <7>
Enter Description:<>:
3 S09°41'44"E 50.636 85.391 45.687 7
====================================
Cheers,
Glen W. Cameron, C.E.T.
City of North Bay, Ontario
City of North Bay, Ontario

 Posts: 32
 Joined: Fri Nov 08, 2002 3:11 pm
 Location: Campbell River, British Columbia
 Contact:
I see the problem. I was trying to use the offset from the second point to calculate a line. The command is used to calculate a point offset a line, not a line perpendicularly distant from a point  a different problem.
Having said all that is there a way to get the result I am looking for?
I have a pin on the east side of a road (Pt 1) and another pin some distance up the road to the north on the west side (Pt 2). I want to calculate the lot corners on the east side of the road north from Pt 1 using a perpendicular offset of 20m to Pt 2 as direction. I could draw a circle of 20m radius around Pt 2 and draw a line from Pt 1 to a tangent point on the circle but that is cheating. Is there a COGO command for this case?
Having said all that is there a way to get the result I am looking for?
I have a pin on the east side of a road (Pt 1) and another pin some distance up the road to the north on the west side (Pt 2). I want to calculate the lot corners on the east side of the road north from Pt 1 using a perpendicular offset of 20m to Pt 2 as direction. I could draw a circle of 20m radius around Pt 2 and draw a line from Pt 1 to a tangent point on the circle but that is cheating. Is there a COGO command for this case?
Hi Glen,
Just so I get this right, you want to create a new point on the East side of the road that 20 m from pt 2 and the azimuth from point #1 to the new point is unknown. The point we want to create must be along a line that is 20 m (Perp) from point #2 to the new line.
There are no other constraints in this problem like a distance or azimuth? Please let me know.
Just so I get this right, you want to create a new point on the East side of the road that 20 m from pt 2 and the azimuth from point #1 to the new point is unknown. The point we want to create must be along a line that is 20 m (Perp) from point #2 to the new line.
There are no other constraints in this problem like a distance or azimuth? Please let me know.
Glen,
If the information above is correct, you can solve for the point on the east side of the road using the Distance/Angle option in COGO. Follow the steps below to see the results you desire.
> COGO
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <3>2
Options: +/ or Pt..Pt+Angle
Enter Azimuth (DDD.MMSS):<>: <ENTER>
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:20.117
Enter the Solve Point: <3>3
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter Distance2: <>: <ENTER>
Enter Angle for Distance/Angle: <>90
Enter the To Point: <3>1
I hope this helps.
If the information above is correct, you can solve for the point on the east side of the road using the Distance/Angle option in COGO. Follow the steps below to see the results you desire.
> COGO
Inverse:Pt..Pt/Curve Inverse:Pt..Pt..Pt
Enter From Point: <3>2
Options: +/ or Pt..Pt+Angle
Enter Azimuth (DDD.MMSS):<>: <ENTER>
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter the Distance: <>:20.117
Enter the Solve Point: <3>3
Options: C#=*/sin/cos/tan... or Pt..Pt(+*/) a Distance
Enter Distance2: <>: <ENTER>
Enter Angle for Distance/Angle: <>90
Enter the To Point: <3>1
I hope this helps.

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